How to solve Problem 5 in Assignment 1

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#1

In assignment 1, problem 5 I am still not figuring out how to do the iteration. I managed to sort the correct result with this code: (…) number_of_happy_tweets = number_of_happy_tweets

perform the calculations here

tweets_not_with_happy_words = 4
for word in tweets:
for word in happy_words:
if word not in tweets:
number_of_happy_tweets = number_of_tweets - tweets_not_with_happy_words

print(number_of_happy_tweets) .

But this is not a correct loop iteration, given that I declare a variable and the calculation is based only on variable declaration. How can I unstuck…?!

#2

I honestly have no idea what you want to achieve here.

Problems:

  • You have 2 for loops, both with the same variable name.
  • You’re checking for word not in tweets, which is true, because tweets usually contain more words (single-word tweets perhaps exists, but not in this assignment).
  • No idea why you’re counting the not happy words, if you can count just the happy ones.

In my opinion your condition should look like this: word in tweet where word variable is one of the words from happy_words list, and tweet variable is one tweet from tweets list.

1 Like
#3

This is how the loop should work here:

Step 1: firstly, get each tweet one by one from the tweets list in a loop
Step 2: then, you need to get each happy word from the list - happy words with another loop inside the first loop
Step 3: then you need to check if that selected happy word is available in a particular tweet that we got from the first loop

If it is available, then you will count it under number_of_happy_tweets

 # step 1
for tweet in tweets:
# step 2
      for word in happy_words:
#step 3
            if word in tweet:
                    number_of_happy_tweets += 1

I hope this clears it a bit.

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#4

I finally figure it out. It was by checking the office hours discusssion on youtube.The final result was very similar to the one proposed here. I wasn’t using the former loop where you iterate over a boolean variable. That’s clever!

#5

I finally figure it out. It was by checking the office hours discusssion on youtube.The final result was very similar to the one proposed here. I wasn’t using the former loop where you iterate over a boolean variable. That’s clever!

1 Like